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0.05x^2-12x-90000=0
a = 0.05; b = -12; c = -90000;
Δ = b2-4ac
Δ = -122-4·0.05·(-90000)
Δ = 18144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18144}=\sqrt{1296*14}=\sqrt{1296}*\sqrt{14}=36\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-36\sqrt{14}}{2*0.05}=\frac{12-36\sqrt{14}}{0.1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+36\sqrt{14}}{2*0.05}=\frac{12+36\sqrt{14}}{0.1} $
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